Question

Find the point equidistant from (0,2) and (0,6), and abscissa 4 units. Pls answer quickly!

Answer 1

Answer:

as given the point is on abscissa point is(4,y)

using distanc formula

√(0-4)² +(2-y)² = √(0-4)² + (6-y)²

16 +4+y² -4y = 16 +36 +y²-12y

8y = 32

y = 4

so the point is(4,4)

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