find the point in the given curve at which slope is -5 y=3x-x²
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Explanation:
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Answer:
x = ±√2
Explanation:
We need to differentiate the equation of the line to find the gradient function:
dy/dx=3x^2-3
We want to find the point at which the slope is a certain value, so we set the gradient function equal to the slope and solve the equation:
let dy/dx=3:3=3x^2-3
Now we can solve this to find the x-coordinates. Then we substitute this into the equation of the line to find the y values.
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