Question

Find the point, M that is five-sixths of the distance from A(-7,2) to B(-1,-4).
A (-1,-3)
B(-2,-3)
C(-1,-4)
D(-2,-4)

Answer 1

Answer:

Distance from A to B =

square root of (x2 - x1)^2 + (y2 - y1)^2

Here x1 is -7 , y1 is 2

x2 is -1 , y2 is -4

In the formula,,

.. = square root of (-1+7)^2 + (-4-2)^2

= square root of 36 + 64

= 10.

The point M is 5/6 of the distance from A to B so

the 5/6 × 10 = 8.3.

So the magnitude of the point is closer to 8.3

So the answer is A(-1, -3).

Answer 2

Answer:

The point of distance is from A to b is 5/6

5/6×10

8.3

Hence -1 and -3 are related to 8.3 So -1 and -3 is the answer....

Hope it helps ~