find the point of interection of the straight line 3y+4x=7 and 4y+3x=7 by drawing their graph and looking for the point where they meet
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1) 4x + 3y = 7
(x1, y1) = (1, 1)
(x2, y2) = (4, -3)
2) 3x + 4y = 7
(x1, y1) = (1, 1)
(x2, y2) = (-3, 4)
from graph:
point of intersection = (1, 1)
(x1, y1) = (1, 1)
(x2, y2) = (4, -3)
2) 3x + 4y = 7
(x1, y1) = (1, 1)
(x2, y2) = (-3, 4)
from graph:
point of intersection = (1, 1)
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