Question

Find the point of intersection of diagonals of the parallelogram whose vertices are (–3, 2), (–4, 4), (1, 4) and (2, 2)

Answer 1

Answer:

The vertices of parallelogram in order are A(−2,−1),B(1,0),C(4,3),D(1,2).

So the diagonals will be AC and BD.

Since the diagonals of a parallelogram bisects each other, so mid-point of

AC or BD will be intersection point of diagonals.

Hence by mid-point theorem, mid-point of AC is

A(−2,−1) and C(4,3)

x=

2

−2+4

=1 and y=

2

−1+3

=1.

so (1,1) is required point.