Find the point of intersection of lines 2x +3 y
- 13 and 5x - y = 7
=
(3,3)
(2,3)
(2,3)
(-3,3)
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The point of intersection of lines,
5x+7y=3...(1) and
2x−3y=7...(2)
Solving (1) and (2) , we get,
(x,y)=(2,−1)
Therefore the equation of line passing through (0,0) and (2,−1) is
(y−0)=
2−0
−1−0
(x−0)
2y=−x
∴x+2y=0 is the required equation
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