Find the point of intersection of the following lines 7x+y+3=0,x+y=0
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Answered by
15
Answer:
point of intersection is (-1/2 , 1/2)
Explanation:
7x + y + 3 = 0 ........(i)
x + y = 0 .........(ii)
subtracted eq (i) and (ii)
7x + y + 3 = 0
x + y = 0
- - = -
...........................
6x + 3 = 0
x = -3/6
x = -(1\2)
putting it in eq(i)
-(1/2) +y = 0
y = 1/2
so point of intersection is (-1/2 , 1/2)
Answered by
4
(-1/2, 1/2)
Explanation:
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