Question

Find the point of intersection of the line joining points (3,7) (2, -4) ar
n of the line joining points (-3,7) (2, -4) and (4,6) (-5,–7). Also
ind the point of intersection of these lines and also their intersection with the axis.​

Answer 1

point of intersection of the line joining points (3,7) (2, -4) and  line joining points (-3,7) (2, -4)  is ( 131/44 , 27/4)

Step-by-step explanation:

line joining points (3,7) (2, -4)

slope = (-4 - 7) / (2 - 3) = -11/-1  = 11

y = 11x  + c

7 = 11*3 + c

=> c= -26

=> y = 11x - 26

=> 11x = y + 26

x = 0  y = -26

y = 0  x = 26/11

intersection with axis   ( 0 , -26)  & ( 26/11 , 0)

line joining points (-3,7) (2, -4)

Slope = (-4 - 7)/(2 -(-3)) = -11/5

y = -11x/5  + c

7 = 33/5 + c

=> c = 2/5

y = -11x/5 + 2/5

=> 5y = 11x + 2

=> 11x = 5y - 1

x = 0 , y = 1/5

y = 0   x = -1/11

intersection with axis   ( 0 , 1/5)  & ( -1/11 , 0)

y + 26  = 5y - 1

=> 4y = 27

=> y = 27/4

  11x  = 27/4 + 26

=> 11x = 131/4

=> x  = 131/44

point of intersection of the line joining points (3,7) (2, -4) and  line joining points (-3,7) (2, -4)  is ( 131/44 , 27/4)

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