Question

find the point of intersection of the line x+2y=0and 2x-3y=7​

Answer 1

Answer:

pt. (2,-1)

Step-by-step explanation:

x+2y=0 - ×2 (multiply by 2)

2x-3y=7 -×1 (multiply by 1)

> 2x+4y=0 -1st eq.

2x-3y=7 - 2nd eq.

_________ (change sign of 2nd eq.)

> 7y = -7

> y = -1

value of y put in eq 1st

> 2x + 4(-1) = 0

> x = 4/2

> x=2

Hence, the point of intersection is (2,-1)