Question

Find the point of intersection of the lines 2x -3y + 1 = 0 and 4y + 3x + 2 = 0

Answer 1

Step-by-step explanation:

please report this ans

Answer 2

Answer:

3x−4y=35........(i)

2x+5y=8

⇒x=

2

8−5y

substituting x in (i)

3(

2

8−5y

)−4y=35

24−15y−8y=70

−23y=46

⇒y=−2

x=

2

8−5(−2)

⇒x=9

So the point of intersection is P(9,−2)

Equation of line joining (2,−9) and P is

y−(−2)=(

2−9

−9−(−2)

)(x−9)

y+2=

−7

−7

(x−9)

y+2=x−9

x−y=11