Question

find the point of intersection of the lines 4x+3y=1 and 3x-y+9=0 . If this point lies on the line (2k-1)x-2y=4;find the value ok k.
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Answer 1

Answer:

Point of intersection of 4x+3y=1 and 3x−y+9=0 is  

4x+3y=1

3x−y+9=0

 13x=126   x=−2

4x+3y=19x−3y=−27

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−6−y+9=0

−y+3=0

y=3

(−2,3) lie on (2k−1)x−2y=4

∴ (2k−1)−2−2×3=4

−4k+2−6=4

−4k=10−2

−4k=8

k=−2