Math, asked by pulakjyotidas2701, 1 year ago

Find the point of intersection of the lines 4x+8y-1=0, 2x-y+1=0

Answers

Answered by prakhar272004
19

Answer:

(3/10,8/5)

Step-by-step explanation:

Answered by DoctorStrange001
0

Answer:

the point of intersection of the lines 4x+8y-1=0, 2x-y+1=0= 3/10 and -7/20

Step-by-step explanation:

In the question

Given:

Two equations:

4x+8y-1=0

2x-y+1=0

To find:

Point of intersection between these two lines given above

Solution:

Now before solving the equation let us first see what is a simultaneous equation?

Simultaneous equations are two or more equations that share common variables

For e.g. x and y.

They are called simultaneous equations because the equations are simultaneously they are solved.

4x+8y-1=0 ...............  (equation 1)

 2x-y+1=0 ................  (equation 2)

Now, we have to multiply this 2x-y+1=0 this equation by a number to make it equal to equation 1

(2x-y+1=0)× 2

4x-2y+1=0

In simultaneous equation we substract one equation from the other

In this we substract equation (2) from equation (1)

we get,

 4x+8y-1=0

-4x+2y+2=0

4x cancels

We are left with;

10y=3

y= 3/10

Now to find x, we substitute the value as follows:

4x+8×3/10-1=0

4x+24/10=1

4x+2.4=1

4x = -1.4

x = -14/40

x = -7/20

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