Find the point of intersection of the lines 4x+8y-1=0, 2x-y+1=0
Answers
Answer:
(3/10,8/5)
Step-by-step explanation:
Answer:
the point of intersection of the lines 4x+8y-1=0, 2x-y+1=0= 3/10 and -7/20
Step-by-step explanation:
In the question
Given:
Two equations:
4x+8y-1=0
2x-y+1=0
To find:
Point of intersection between these two lines given above
Solution:
Now before solving the equation let us first see what is a simultaneous equation?
Simultaneous equations are two or more equations that share common variables
For e.g. x and y.
They are called simultaneous equations because the equations are simultaneously they are solved.
4x+8y-1=0 ............... (equation 1)
2x-y+1=0 ................ (equation 2)
Now, we have to multiply this 2x-y+1=0 this equation by a number to make it equal to equation 1
(2x-y+1=0)× 2
4x-2y+1=0
In simultaneous equation we substract one equation from the other
In this we substract equation (2) from equation (1)
we get,
4x+8y-1=0
-4x+2y+2=0
4x cancels
We are left with;
10y=3
y= 3/10
Now to find x, we substitute the value as follows:
4x+8×3/10-1=0
4x+24/10=1
4x+2.4=1
4x = -1.4
x = -14/40
x = -7/20
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