Question

Find the point of intersection of the lines 5x − 7y + 1 = 0 and 2x + 5y − 11 = 0​

Answer 1

Answer:

Hey Mate!!

5x - 7y + 1 = 0

⇒ 5x - 7y = -1

⇒ 10x - 14y = -2                               ...(1)

2x + 5y - 11 = 0

⇒ 2x  + 5y = 11

⇒ 10x + 25y = 55                          ...(2)

By (2) - (1),

10x + 25y - 10x + 14y = 55 - (-2)

→ 39y = 55 + 2

→ 39y = 57

→ y = 57/39

→ y = 19/13

By y in (1),

10x - 14y = -2

→ 10x - 14(19/13) = -2

→ 10x - 266/13 = -2

→ 10x = 266/13 - 3

→ 10x = (266 - 39)/13

→ 10x = 227/13

→ x = 227/13 × 1/10

→ x = 227/130

Thus, the point of intersection is (227/130, 19/13).