find the point of intersection of the lines x+3y-6=0 and -3x+y=7
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Answer:
Point of intersection is (-1.5,2.5)
Step-by-step explanation:
L1: x+3y-6= 0--------Eq(1)
L2: y-3x-7=0----------Eq(2)
Now Multiply Equation 1 by 3
3x+9y-18 = 0 -----------Eq(3)
Now add equation 2 and 3
y-3x-7+3x+9y-18=0
10y-25=0
10y=25
y=2.5
-3x+2.5 = 7
hence 3x= 2.5-7 = -4.5
therefore x= -4.5/3 = -1.5
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