Question

Find the point of intersection of the lines x + y = 7 and y= -3 both algebraically and graphically.​

Answer 1

Answer:

Correct option is

C

(6,1)

For line 2x−3y=9

 x 0 6 y −3 1For line x+y=7

 x 5 2 y 6 1

x+y=7 ----- (1)

2x−3y=9 ----- (2)

From equation (1)

y=7−x  ------ (3)

Assume the value of x=5,6 and put those values in equation (3)

If x=5,y=7−5=2

If x=6,y=7−6=1

Now plotting (5, 2), (6, 1) and joining them, we get a straight line.

From equation (2),

2x−3y=9

y=32x−9 ------ (4)

Assume the value of x=0,6 and put those values in equation (4)

If x=0,y=32x−9=32(0)−9=3−9=−3

If x=6,y=32(6)−9=312−9=33=1

Plotting (0,−3),(6

Step-by-step explanation:

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Answer 2

Concept

Point of intersection means the point at which two lines intersect

Given

We have given two lines x + y = 7 ....(1)  and y = -3    ... (2).

Find

We are asked to determine the point of intersection of given two lines

and represent these lines graphically also.

Solution

For point of intersection we will solve these lines .

Putting y = -3 in equation , we get

$x+(-3)=7\\x-3=7\\x=10$

Therefore , the point of intersection will be  $(10,-3)$ .

Graphically :-

For  $x+y=7$

When x = 0 , y = 7

When x = 7 , y = 0

For $y= -3$

This line will be parallel to x - axis

Hence point of intersection is (10, -3)

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