Find the point of intersection of the straight lines 3y+4x=7 and 4y+3x=7, by drawing their graphs and looking for the point where they meet.
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i ) Given 4x + 3y = 7
_______
| x | 1 | -2 |
_______
| y | 1 | 5 |
_______
( 1 , 1 ) , ( -2 , 5 )
ii ) 3x + 4y = 7
_______
| x | 1 | 5 |
_______
| y | 1 | -2 |
_______
( 1 , 1 ) , ( 5 , -2 )
Plotting the points on the graph and
joing them we get two intersecting
lines .
Intersecting point = ( 1 , 1 )
•••••
_______
| x | 1 | -2 |
_______
| y | 1 | 5 |
_______
( 1 , 1 ) , ( -2 , 5 )
ii ) 3x + 4y = 7
_______
| x | 1 | 5 |
_______
| y | 1 | -2 |
_______
( 1 , 1 ) , ( 5 , -2 )
Plotting the points on the graph and
joing them we get two intersecting
lines .
Intersecting point = ( 1 , 1 )
•••••
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Answered by
3
Given 4x + 3y =
( 1 , 1 ) , ( -2 , 5 )
ii ) 3x + 4y = 7
( 1 , 1 ) , ( 5 , -2 )
Plotting the points on the graph and
joing them we get two intersecting
lines .
Intersecting point = ( 1 , 1 )
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