Find the point of intersection of y axis and the perpendicular bisector of (2, - 3) and( - 4, 1)
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Midpoint of given line=(2-4)/2,(-3+1)/2
=(-1,-1)
Slope of line=-3-1/2+4=-2/3
Slope of perpendicular bisector=-1/-2/3=3/2
Let equation of perpendicular bisector be y=mx+c
Now m=3/2
y=3x/2+c
2y=3x+2c
(-1,-1) lies on the given line
-2=-3+2c
2c=3-2
2c=1
Equation of bisector is 2y=3x+1
Equation of y axis x=0
Substituting,
2y=1
x=0
Point of intersection (1/2,0)--------------(Ans)
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