find the point of the intersection of the line 2x-y+3=0 and 3x-y+1=0
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2x - y + 3= 0 ......(1)
3x - y + 1= 0 ........(2)
subtract 1 from 2
3x - y + 3 = 0
2x - y + 1 = 0
- + -
x - 0 + 2 = 0
=》x = -2
put value of x in (1)
2(-2) - y +1 = 0
-4 - y = -1
- y = - 1+ 4
y = - 4
at co-ordinate (-2, -4) both line will intersect.....
hence, question is solved
enjoy ur Lyf guys...
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