find the point of x axis which is equidistant from (-6,4) and (2,-4)????
Answers
Answered by
1
Answer:
Correct option is
C
(3,0)
Let the point on the x-axis be (x,0)
Distance between (x,0) and (7,6)=
(7−x)
2
+(6−0)
2
=
7
2
+x
2
−14x+36
=
x
2
−14x+85
Distance between (x,0) and (−3,4)=
(−3−x)
2
+(4−0)
2
=
3
2
+x
2
+6x+16
=
x
2
+6x+25
As the point (x,0) is equidistant from the two points, both the distances
calculated are equal.
x
2
−14x+85
=
x
2
+6x+25
=>x
2
−14x+85=x
2
+6x+25
85−25=6x+14x
60=20x
x=3
Thus, the point is (3,0)
Answered by
0
Step-by-step explanation:
xsx-v svt-ybj
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