Question

find the point of x axis which is equidistant from the points (2, - 2) and (-4, 2)​

Answer 1

Step-by-step explanation:

Let P(x,0) be a point on X-axis

PA = PB

PA2 = PB2

(x - 2)2 + (0 + 2)2 = (x + 4)2 + (0 - 2)2 x2 + 4 - 4x + 4 = x2 + 16 + 8x + 4 -4x + 4 = 8x + 16 x = -1 P(-1,0)

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