Question

Find the point of y-axis which is equidistant from the points (-5, -2) and (3, 2).

Answer 1

Answer:

Find the point of y-axis which is equidistant from the points (-5, -2) and (3, 2).

we should think the point as p(0,Y)

And by the problem,

Pa=Pb

ANSWER:-

Therefore, the point is (0,-2)

Answer 2

Answer:

⇒√(0+5)²+(y+2)²=√(0-3)²+(y-2)² (Using Distance Formula)

⇒√(25+y²+4y+4)=√(9+y²-4y+4)

⇒√(y²+4y+29)=√(y²-4y+13)

⇒y²+4y+29=y²-4y+13

⇒4y+29=13-4y

⇒8y=16

⇒y=2