Question

find the point on a-axis that is equstidistant from 2, 3 and 4,-1​

Answer 1

Answer:

LET A POINT ON X-AXIS IS (x, 0)

nOW (x, 0) IS EQUIDISTANT FROM (2, 3) AND (4, -1)

(x-2)^2+(0-3)^2 = (x-4)^2+(0+1)^2

x^2-4x+4+9 = x^2-8x+16+1

-4x+13 = -8x +17

-4x+8x = 17 - 13

4x = 4

x = 4/4 = 1

so point on x axis is (1. 0)

Step-by-step explanation: