Question

Find the point on axis which is equidistant
from (2,-5) and (-2,9
)​

Answer 1

Answer:

let the point be (x,y)

$x.y = \frac{ - 2 - 2}{2}. \frac{9 + 5}{2}$

$x.y = \frac{ - 4}{2}. \frac{14}{2}$

$x.y = - 2.7$

•°•x=-2 & y=7

•°• (-2,7) is equidistant from the points

hope it helps you......