Question

Find the point on the axis which is equidistance from (2,-5)and (-2,9)​

Answer 1

Answer:

let (x,y) is equidistance from the point (2,-5) and (-2,9)

$x = \frac{ - 2 - 2}{2} = \frac{ - 4}{2} = - 2$

$y = \frac{9 - ( - 5)}{2} = \frac{9 + 5}{2} = \frac{14}{2} = 7$

Step-by-step explanation:

(x,y) = (-2,7)