Find the point on the axis which is equidistant from the points (2, - 5) and (- 2, 9). Also find the area of the isosceles triangle so formed.
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(x2-2)^2+(y2+5)^2=(x2+2)^2+(y2-9)^2
x2^2-4x2+4+y^2+10y+25=x2^2+4x2+4+y2^2-18y+81
x2^2-4x2+4+y^2+10y+25=x2^2+4x2+4+y2^2-18y+81
Alanaaron:
How to find area of isosceles triangle
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