Question

find the point on the curve y=2x3-3x23x-2 at which the tangent line's are parellel to the 3x-y+7=0​

Answer 1

Answer:

HEY HERE IS UR ANSWER --

Step-by-step explanation

y=2x  

3

−15x  

2

+36x−21

dx

dy

​

=6x  

2

−30x+36

Now,  

dx

dy

​

=0

or, 6x  

2

−30x+36=0

or, x  

2

−5x+6=0

or, x  

2

−3x−2x+6=0

or, x(x−3)−2(x−3)=0

x=2,x=3

when x=2

(y)  

x=2

​

=2.2  

3

−15.2  

2

+36.2−21=16−60+72−21=7

(  

dx

dy

​

)  

x=2

​

=6.2  

2

−30.2+36=24−60+36=0

(y)  

x=3

​

=2.3  

3

−15.3  

2

+36.3−21=6

Points are (2,7),(3,6)

The equation of tangent at (2,7) parallel to x-axis y−7=0(x−2) y−7=0

The equation of tangent at (3,6) parallel to x-axis is y−6=0(x−3) or y−6=0.