Question

Find the point on the curve y=x^3-11x+5 at which the tangent has the equation y=x-11

Answer 1

Answer:

Step-by-step explanation:

Given : y=x3−11x+5

dy /dx=3x2−11----(1)

The equation of the given tangent is y=x−11

Now equating this slope to equ(1)

3x2−11=1

3x2=12

x2=4

x=±2

When x=2,y=−9

When x=−2,y=−13

Hence the point is (2,−9)

Answer 2

Answer:

(2,-9)

Step-by-step explanation:

y=x^3-11x+5

differentiate on both sides..

dy/dx=3x^2-11 ___eq.1

given, y=x-11

diff.b/s

dy/dx=1___eq.2

now equating eq.1 and eq.2

3x^2-11=1

X=±2

if x =2,y = -9

x = -2,y = -13

thus the point is (2,-9)