Question

Find the point on the curve y = x2 – 5x + 4
at which the tangent is parallel to the line
3x + y = 7.​

Answer 1

Answer:

Let (x1, y1) be the required point. Given tangent is similarly to the line ⇒ m1 = m2 ⇒ 2x1 – 5 = -3 ⇒ 2x1 = -3 + 5 = 2 ⇒ x1 = 1 Substituting x1 = 1 in the curve. y1 = 1 – 5 + 4 = 0 So the required point is (1, 0)Read more on Sarthaks.com - https://www.sarthaks.com/878655/find-the-point-on-the-curve-y-x-2-5x-4-at-which-the-tangent-is-parallel-to-the-line-3x-y-7?show=878659