Question

find the point on the line 2x+5=20, whose abscissa is 5/2 times its ordinate.
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Answer 1

I hope you understand thanks

Answer 2

Step-by-step explanation:

Given Question:-

Find the point on the line 2x+5=20, whose abscissa is 5/2 times its ordinate.

Correct Question:-

Find the point on the line 2x+5y = 20, whose abscissa is 5/2 times its ordinate.

Solution:-

Let the required point be (a,b)

Let the Ordinate of the point be b

Let the Abscissa of the point = a

Abscissa = 5/2 times the ordinate

a = 5/2 times its ordinate.

a= 5/2 (b)

a= 5b/2

The point = (5b/2 , b)

Given line = 2X+5Y = 20------(1)

The point is on the line 2X+5Y = 20

We know that

If a point lies on a line then it must be a solution of the line.

Put X= 5b/2 and Y=b in (1)

=> 2(5b/2)+5(b) = 20

=> 5b + 5b = 20

=> 10 b = 20

=> b = 20/10

=> b = 2

Then a = 5b/2

=> a = 5×2/2

=> a = 5

Abscissa = 5

Ordinate = 2

The point = (5,2)

Answer:-

The required point for the given problem is

(5,2).

Used Concept:-

• If a point lies on a line then it must be a solution of the line.