Question

Find the point on the line 3x-4y-1=0 which are at a distance of 5 units from the point (3, 2).

Answer 1

Answer:

Step-by-step explanation:

Let the points be (x,y) which lie on 3x-4y-1=0 and are at a distance 5 units from(3,2)

Slope of this given line is 3/4

Therefore tan@ =3/4 hence sin@=3/5 and cos@=4/5 given r may be positive or negative as it is not mentioned in which direction we should find so we take both directions

Finally by using parametric equations here:- @ means THETA

X=3+(5)(4/5)=7 case 1 when r is +ive

Y=2+(5)(3/5)=5

X=3-(5)(4/5)=-1 case 2 when r is -ive

Y=2-(5)(3/5)=-1

Finally the coordinates are (7,5) and (-1,-1) hence by substituting them in given equation they satisfy the condition