Question

Find the point on the X-axis and which is equidistant from A (-3,4) and B(1,-4)​

Answer 1

Answer:

Let the point on the x-axis be P(a, 0).

PA=

(a−(−3))

2

+(0−4)

2

=

(a+3)

2

+16

PB=

(a−1)

2

+(0−(−4))

2

=

(a−1)

2

+16

PA

2

=PB

2

⇒(a+3)

2

+16=(a−1)

2

+16

⇒a

2

+6a+9=a

2

−2a+1

⇒8a=−8

⇒a=−1

(a,0)=(−1,0)