Question

find the point on the x-axis at a distance of 2√5 from the point(7,4) how many ,such points are there​

Answer 1

Answer:

Let Point P=(x,0)

A=(7,−4)

Given A=(7,−4)

AP=2

5

(x−7)

2

+4

2

=20

(x−7)

2

=20−16=4

x−7−2x−7=−2

x=9x=5

(9,0)(5,0)

∴Two such points are there (9,0) & (5,0)