Question

find the point on the x-axis which are at a distance of 2rute 5 from the point (7,-4) how many such point are there ​

Answer 1

question_answer Answers(2)

Co-ordinates of point on x-axis be (x, 0) which is at a distance of 2√5 from point (7, –4). It is given that the distance between points (x, 0) and (7, –4) is 2√5. ⇒ [ ( 7 -x )2 + ( -4 – 0)2 ] = 2√5 . ∴ x = 5 and 9.

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