Question

find the point on the X axis which are at a distance of 2√5from the points 7,-4how many such point their​

Answer 1

Answer:

the point lie in x axis, y = 0

assume that point is (x,0)

distance between (x, 0)and (7,-4) = 2√5

(7-x)² + (-4)² = (2√5)²

49+x²-14x+16 = 20

x²-14x+45 = 0

(x-9)(x-5) = 0

x = 5,9

there are Two points such that (5,0) , (9,0)