Question

Find the point on the X-axis, which are at a distance of 2√5 from the point (7, - 4). How many such points are there?​

Answer 1

Solution: We know that, every point on the X-axis in the form (x, 0). Let P(x, 0) the point on the X-axis have 2√5 distance from the point Q (7, – 4). Hence, there are two points lies on the axis, which are (5, 0) and (9, 0), have 2V5 distance from the point (7, – 4).

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Answer 2

Answer:

We know that, every point on the X-axis in the form (x, 0). Let P(x, 0) the point on the X-axis have 2√5 distance from the point Q (7, – 4). Hence, there are two points lies on the axis, which are (5, 0) and (9, 0), have 2V5 distance from the point (7, – 4)...

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