find the point on the x axis which is equal distanes from 7, 6 and-3, 4
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Answered by
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by distance formula
(x,0) and (7,6)=√(7-x)²+(6-0)²= √x²-14x+85
(x,0) and (-3+4)= √(x+3)²+(0-4)²=√x²+6x+25
√x²-14x+85= √x²+6x+25
cancel root both side
x²-14x+85=x²+6x+25
85-25=20
60=20x
x=60/20
x=3
(x,0) and (7,6)=√(7-x)²+(6-0)²= √x²-14x+85
(x,0) and (-3+4)= √(x+3)²+(0-4)²=√x²+6x+25
√x²-14x+85= √x²+6x+25
cancel root both side
x²-14x+85=x²+6x+25
85-25=20
60=20x
x=60/20
x=3
kajal2016:
mane que acche sai nhi padha
Answered by
1
hey you use here distance formula. Now ,one point is let on xaxis here y is equal to zero.Find distance from the let point with given point .and similarly find with other . and take it equal.then find the value of let point here value of y is zero
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