Question

Find the point on the x–axis which is equi distant from (2, –5) and (–2, 9)​

Answer 1

Thank your kids to 2332(456(&56;857)76$375(565757?;8()85448

Answer 2

Step-by-step explanation:

The point is on the x axis. Hence we can assume the coordinate of the point as (h,0).

Now the point is equidistant from (2,-5) and (-2,9).

So

Simplifying this we get

Or 8h = -56 or h= -7

Hence the point is (-7,0) which is equidistant from (2,-5) and (-2,9).