Question

Find the point on the X-axis which is equidistant from (2, –5) and (–2, 9).

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Answer 1

Answer:

The point is on the x axis. Hence we can assume the coordinate of the point as (h,0).

Now the point is equidistant from (2,-5) and (-2,9).

So

Simplifying this we get

Or 8h = -56 or h= -7

Hence the point is (-7,0) which is equidistant from (2,-5) and (-2,9).

Answer 2

Step-by-step explanation:

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