Question

find the point on the x axis which is equidistant from (2
,-5),(-2,9)​

Answer 1

Answer:

$\huge\mathfrak\purple{☆Answer☆}$

Step-by-step explanation:

Let the point be (x, 0) as it is on x-axis so it's ordinate is 0.

APPLYING DISTANCE FORMULA=>

√(x-2)^2+(0-(-5)^2=√(x-(-2)^2+(0-9)^2

=>(x-2)^2+(5)^2=(x+2)^2+(-9)^2

=>x^2+4-4x+25=x^2+4+4x+81

=>x^2-4x+29=x^2+4x+85

=>x^2-x^2-4x-4x=>85-29

=>-8x=56

=>x=-56/8

=>x=-7.

So abscissa is -7 hence the point is (-7,0).

HOPE IT HELPS.