Question

find the point on the x axis which is equidistant from (2,-5) (-2,9)​

Answer 1

Step-by-step explanation:

Let the point on x axis be(x, 0)

then (x-2)^2+(0+5)^2=(x+2)^2+(9-0)^2

=x^2+4-4x+25=x^2+4+4x+81

=-4x+25=4x+81

=8x=-56

=x=-7

Hence, the point on the x axis which is equidistant from (2,-5) (-2,9) is (-7,0)

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