Question

Find the point on the x-axis which is equidistant from (2.-5) and (-2,9).
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Answer 1

let (x,y) is equidistance from (2;-5) and (-2,9)

$x = \frac{ - 2 - 2}{2} = \frac{ - 4}{2} = - 2$

$y = \frac{9 - ( - 5)}{2} = \frac{9 + 5}{2} = 7$

(x,y) = (-2,7)

Answer 2

Answer:

Hope it works!!

#shruti