Question

Find the point on the x axis, which is equidistant from (
2, - 5) and (- 2 , 9. )​

Answer 1

Answer:

( - 7, 0 )

Step-by-step explanation:

As the point is on x axis, its y cordinate must be 0.

So let the point be ( a, 0 ).

As it is equidistant from the given points.

= > distance b/w ( 2, - 5 ) and ( a, 0 ) = distance b/w ( - 2, 9 ) and ( a, 0 )

Using distance formula,

= > √{ ( 2 - a )² + ( - 5 - 0 )² } = √{ ( - 2 - a )² + ( 9 - 0 )² }

= > ( 2 - a )² + 5² = ( - 2 - a )² + 9²

= > 4 + a² - 4a + 25 = 4 + a² + 4a + 81

= > 25 - 81 = 4a + 4a

= > - 56 = 8a

= > - 7 = a

Hence required coordinate should be ( - 7, 0 )