Question

Find the point on the x axis which is equidistant from (2,-5) and (-2,9)

Answer 1

heya ☺

it's easy .

let the given point be A(2,-5) and B(-2,9) and p point be p(x,0)

PA=PB=)PA^2=PB^2

=)(x-2)^2+(0+5)^2=(x+2)^2+(0-9)^2

=)x^2+4-4x+25=x^2+4x+4+81

=)-8x=56

x=-56/7

x=-8
point p will be (-7,0)

hope it help you

@rajukumar☺

=)



=)y^2-4y+



hope it help you..

@rajukumar☺

Answer 2

Heya   

Your answer is here....

Let the points be A (2, -5) and B (-2, 9). 
Let the third point be C.

It is given that the third point is on x axis. So, C (k, 0)   {Becoz. On x-axis, y=0 and we take k as x- coordinate).

Now, ATQ.
AC = BC.

So,
AC² = BC².

=> (2-k)² + (-5 -0)²    = (k+ 2)² + (0 - 9)²
=> 4 + k² - 4k + 25 = k² + 4 + 4k + 81 
=> -4k - 4k = 81 -25
=> -8k = 56
Hence, k = -7.

So, the coordinate C is C (-7, 0) which is equidistant from A and B.

Hope it helps ...........

#Find the point on the x axis which is equidistant from (2,-5) and (-2,9).