Find the point on the X-axis which is equidistant from (2,-5)&(-2,9)
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Step-by-step explanation:
We have to find a point on x-axis. Therefore, its y-coordinate will be 0. Let the point on x-axis be (x,0) (x - 2)2 + 25 = (x - 2)2 + 81 x2 + 4 - 4x + 25 = x2 + 4 + 4x + 81 8x = 25 -81 8x = -56 x = -7 Therefore, the point is ( - 7, 0).Read more on Sarthaks.com - https://www.sarthaks.com/2428/find-the-point-on-the-x-axis-which-is-equidistant-from-2-5-and-2-9
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