Question

Find the point on the x-axis which is equidistant from (2,-5) and (-2,9)​ by distance formula.

Answer 1

Answer:

let the point be (x,0)

√(x-2)^2+(0+5)^2=√(x+2)^2+(0-9)^2

squaring both sides

(x-2)^2+25=(x+2)^2+81

x^2+4-4x+25=x^2+4+4x+81

-8x=81-25

-8x=56

x=-7

point is (-7,0)