Question

Find the point on the x-axis which is equidistant from (2,-5) and (-2,9).​

Answer 1

Answer:

Hence, point on the x-axis which is equidistant from (2,−5) and (−2,9) is (−7,0).

Answer 2

Answer:

let the point be (x, 0), then, by distance formula we have,

$\sqrt{ {(x - 2)}^{2} + {(0 + 5)}^{2} } = \sqrt{ {(x + 2)}^{2} + {(0 - 9)}^{2} } \\ = > \: {(x - 2)}^{2} + 25 = {(x + 2)}^{2} + 81 \\ = > \: {x}^{2} + 4 - 4x + 25 = {x}^{2} + 4 + 4x + 81 \\ = > \: 8x = - 56 \\ = > \: x = - 7$

Hence, (x, 0) =(-7, 0)

Step-by-step explanation:

Hope this will be helpful