Question

find the point on the x axis which is equidistant from (2,-5) and (-2,9).​

Answer 1

Answer:

X = 2,1,0,-1,-2,-3,-4,-5. = -2,-1,0,1,2,3,4,5,6,7,8,9

both have no equal opportunity..

Step-by-step explanation:

THANKS

Answer 2

Answer:

(2,0)

Step-by-step explanation:

As the point is on x axis then the y coordinate of that point is 0

and for x coordinate we apply mod section formula,i.e.,

$\frac{x2 + x1}{2}$

$\frac{9 + ( - 5)}{2}$

$\frac{9 - 5}{2}$

$\frac{4}{2}$

2

therefore the x coordinate is 2

So, the point on the x axis which is equidistant from (2,-5) and (-2,9) is (2,0)