Question

Find the point on the X-axis which is equidistant from A(-3, 4) and B (1,-4)​

Answer 1

Answer:

see the above attachment hope you understood

Answer 2

Answer:

Let the point be P(x, 0)

Step-by-step explanation:

According to statement

PA = PB

$\sqrt{ {(x + 3)}^{2} + {(0 - 4)}^{2} } = \sqrt{ {(x - 1)}^{2} + {(0 \: + 4)}^{2} } \\ squaring \: both \: sides \\ {x}^{2} + 9 + 6x + 16 = {x}^{2} + 1 - 2x + 16 \\ 8x = - 8 \\ x = - 1$

So point on x axis is P(-1, 0).