Question

find the point on the x-axis which is equidistant from point A ( -3,4) and B ( 1,4).

Next step what should I do​

Answer 1

A ( -3 , 4 ) ≈ X1 Y1

B ( 1 ,4 ) ≈ X2 Y2

By the distance formula

$➠\sqrt{ {(x2 - x1)}^{2} +({y2 - y1)}^{2}}$

$➠\sqrt{ {(1 - ( - 3)}^{2} + {(4 - 4)}^{2} }$

$➠\sqrt{ {(4)}^{2} + {(0)}^{2} }$

$➠\sqrt{16}$

$➠ \: 4 \: units$

Answer 2

Answer:

$d= \sqrt{( {1 - ( - 3)}^{2} } + ( {4 - 4) }^{2}$

$= \sqrt{ {(1 + 3)}^{2} } + {0}^{2}$

$= \sqrt{ {4 }^{2} } + {0}^{2}$

$= \sqrt{16}$

$= 4$