Question

Find the point on the x-axis which is equidistant
from the points (2,-5) and (-2.9)​

Answer 1

Answer:

Step-by-step explanation:

Let the point be (x,y)

So distance from (2,-5)

=√{(2-x)²+(-5-0)²}

=√{4+x²-4x+25} _____(1)

Distance from point (-2,9)

=√{(-2-x)²+(9+0)²}

=√{4+x²+4x+81} ______(2)

Since (1) and (2) are equal

√{4+x²-4x+25} = √{4+x²+4x+81}

Squaring both sides

4+x²-4x+25=4+x²+4x+81

-8x=56

x= -7

Hence the point is (-7 ,0)